Calculating Total Length of Car's Breaking Path with a=4 m/s^2

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Homework Help Overview

The problem involves calculating the total length of a car's braking path given a specific acceleration and a condition regarding the distance covered in the first second of braking. The subject area is kinematics, particularly focusing on motion under constant acceleration.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the use of standard constant acceleration equations and the relationship between the total stopping distance and the distance covered in the first second. Some question the original poster's setup and assumptions regarding the braking distance.

Discussion Status

The discussion includes attempts to clarify the problem and explore the equations involved. Some participants have offered guidance on how to approach the problem, while others express uncertainty about the original poster's attempts and the provided solution.

Contextual Notes

There is a mention of a specific condition where the car covers one fifth of the total distance in the first second of braking, which may influence the calculations. The original poster has expressed difficulty in solving the problem and has been encouraged to share their attempts for more targeted assistance.

Hristijan1992
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Homework Statement


During the testing of the break of car, observed that in the first second of the start of breaking the car past one fifth of the total path. What is the total length of the traveled way during the breaking, if the acceleration is a=4 m/s^2 ?

Homework Equations





The Attempt at a Solution

https://www.physicsforums.com/newthread.php?do=newthread&f=154
 
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Welcome to PF!

Hi Hristijan1992! Welcome to PF! :smile:

(btw, it's "brake" and "braking" :wink:)

erm :redface: … your solution hasn't come out, the link isn't working!

I assume you used the standard constant acceleration equations?

Show us what you get. :smile:​
 
The solution is : s=a/2(sqrt(5)/(sqrt(5)-2))^2 but i don't know how can i solve the problem...
 
Hi Hristijan1992! :wink:

(have a square-root: √ and try using the X2 icon just above the Reply box :wink:)

Call the stopping distance s, and write one of the standard constant acceleration equations for distance = s (with vf = 0), and another for distance = s/5 (with t = 1).

Show us what you get. :smile:​
 
i can't solve it ... Please if anyone can show me what is the problem... i must solve it ...
 
Sorry, on this forum you have to do it yourself. :wink:

Show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:​
 
yay :D :)) i solve it. Thank you very much :))
 

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