PDA

View Full Version : An exact(?) expression for the fine structure constant


Hans de Vries
Sep20-04, 12:52 PM
Just for the record:


\ \alpha^{-\frac{1}{2}}\ +\ \alpha^\frac{1}{2}\mu\ =\ e^{\pi^2/4}


Where \alpha, the fine-structure constant = 1/137.03599911 (46)
and \mu=1+\frac{\alpha}{2\pi} is Schwingers first term of the electrons
magnetic moment anomaly which is a function of \alpha as well.

\alpha^\frac{1}{2} is the probability for an electron to emit or absorb a photon.

Fill in 1/137.03599911 for \alpha and you'll get for pi:

3.14159265263 which only differs in the 10th digit with the real value:
3.14159265358...

Using the exact value for pi results in a value for the fine structure
constant of: 1/137.03599952837 which is within the measurement range.

Does it mean anything? maybe, maybe not.

Regards, Hans