Proving the Limit of a Complicated Function using Variables and Compositions

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Homework Help Overview

The discussion revolves around proving the limit of a composition of functions involving variables. The original poster presents a limit problem that requires demonstrating the relationship between functions f, g, and h as x approaches a.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the limit of a composition of functions and discuss the implications of variable substitutions. There is an attempt to clarify the steps involved in transitioning from one limit to another.

Discussion Status

Some participants have provided guidance on the reasoning process, and there appears to be a productive exchange of ideas regarding the limit. Multiple interpretations of the problem are being explored, but no explicit consensus has been reached.

Contextual Notes

Participants are considering the expectations of their teacher regarding the rigor of the proof, indicating a potential constraint in how the problem should be approached.

Hygelac
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I'm stuck on one complicated limits problem, wondering if any of you could help me :) usually I am pretty fine with limits but this one uses all variables and has functions in it. Anyways, here it is:

f(a) = b, g(b) = c, h(c) = d
prove lim[x->a](h°g°f)(a) = d

(° = "of")

Can anyone help me?
 
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lim[x->a](h(g(f(x)))) = d eh?

Well as x->a, f(x)->b
let y = f(x)
So now we have lim[y->b](h(g(y)))

as y->b, g(y)->c

Make sense? I guess the rest is obvious
 
Thanks for your help, I just thought of something else, too. Seems like this works and is very easy, could you do just a quick check of it and see if it makes sense?

f(a) = b, g(b) = c, h(c) = d

lim[x->a](h(g(f(a)))) = d

f(a) = b, so g(f(a)) = g(b)
g(b) = c, so h(g(b)) = h(c)
h(c) = d, which solves the problem
 
Looks good to me. You may want to play it safe I'm not sure how meticulous your teacher expects you to me but I would accept that answer :)
 
Thanks a bunch :)
 

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