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fasterthanwoo
Nov18-10, 06:34 PM
Thanks for the help guys.

Bohrok
Nov18-10, 07:08 PM
You need equal amounts of the elements O and H on both sides of the equation. Try adding H2O on the left side and balance the elements, then balance the charges.

fasterthanwoo
Nov18-10, 07:17 PM
Thanks for the help guys.

symbolipoint
Nov18-10, 07:37 PM
I am still having some trouble with this.

The MnO4 is being reduced.

The oxidation state of MnO4 is 7. The oxidation state of MnO2 is 4. Therefore I need three e- to reduce?

Is it needed to have H2O on the left side of the reaction?

Thank you.

Yes. Three electrons to reduce Mn. Now balance the electrons for both half-reactions before worrying about the H's and the O's and the H2O's.

fasterthanwoo
Nov18-10, 07:50 PM
Thanks for the help guys.