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Maria
Oct6-04, 03:22 AM
Can someone help me with this:cos^2x = 2cosxsinx?
X E 0,360..
I really haven`t understood this trigonomy stuff yet.. :yuck:

matt grime
Oct6-04, 04:04 AM
Did you see that sticky about posting homework?

Hint: forget trig for now, and simplify


a^2=ab.

Motifs
Oct6-04, 12:22 PM
Can someone help me with this:cos^2x = 2cosxsinx?
X E 0,360..
I really haven`t understood this trigonomy stuff yet.. :yuck:
Hi, Maria, I am Susan, :redface: What matt told you to do is something like this: :blushing:
cosx(cosx-2sinx) =0
cosx=0 OR tanx=1/2

Maria
Oct7-04, 04:51 AM
Can you explain it to me a bit more?

I need to understand the whole prosess, because I have to explain it to someone else on thursday.. I need 4 angles..

Zurtex
Oct7-04, 06:11 AM
What you basically have is:

a^2 = ab

You can wright this is:

a^2 - ab = 0

a(a - b) = 0

This tells you that either a is 0 or a - b is 0, right? Well try and follow that procedure out with your trig functions.

Maria
Oct11-04, 10:11 AM
I got it right :smile: Thanks a lot