Revolutions problem

[guru]

An electron of mass (m=9.1*10^(-31)kg) orbits a proton at a distance of 5.3*10^(-11)m. The proton pulls on the electron with an electric force of 9.2*10^(-8)N.
How many revolutions per second does the electron make?

This is what I did:

m=9.1*10^(-31)kg
v=5.3*10^(-11)m
T=9.2*10^(-8)N

V=sqrt(rT/m)= 23147876.27 m/s

angular velocity (w) = (v/r) = 4.38^(16) rad/s
w*(1 rev/(2(pi)rad)) = 9.17*10^9 rev/s

I was told the answer was wrong.
Please help

[kenhcm]

The electrostatic force serves as the centripetal force. It is given by F = mrw^2. Once w has been determined, w/(2 pi) will be the frequency.

Best regards,
Kenneth