View Full Version : How does this fit the equation of a hyperbola?
sparkle123
Apr3-11, 01:45 PM
As far as I know, a hyperbola has the equation
http://i1206.photobucket.com/albums/bb443/thehappymelon/a50e632b.png
So how does this (below) work?
http://i1206.photobucket.com/albums/bb443/thehappymelon/04b1aca6.png
Thanks!
I like Serena
Apr3-11, 03:25 PM
Do you have the definitions of v0, S and [S]?
sparkle123
Apr3-11, 03:40 PM
[S] is substrate concentration
vo is the initial rate of an enzyme-catalyzed reaction
Thanks!
I like Serena
Apr3-11, 04:17 PM
[S] is substrate concentration
vo is the initial rate of an enzyme-catalyzed reaction
Thanks!
Ah, so we're talking about a model where vo is predicted based on a substrate concentration [S].
I presume the model leads to the formula you presented?
I guess you should know that y = 1/x also describes a hyperbola with its asymptotes aligned with the coordinate axes.
If you would draw a plot of your formula, you'll see that it is a hyperbola.
You can see that for instance here: http://www.wolframalpha.com/input/?i=Plot[%282+x%29%2F%283+%2B+x%29%2C+{x%2C+-15%2C+15}]
The parameters a and b seem to be arbitrary parameters that do not describe the geometric shape of the hyperbola.
I could find out what the actual geometric parameters are, but I suspect that's not really relevant in your case?
I guess that was is relevant in your case is the location of the asymptotes, which are at [S] = -b and at v0 = a .
sparkle123
Apr3-11, 04:26 PM
Thank you! :)
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