What is the Electric Field at the Surface of the Wire and Cylinder?

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Homework Help Overview

The problem involves calculating the electric field at the surface of a wire and a surrounding cylinder, given specific dimensions and a voltage applied between them. The subject area pertains to electrostatics and electric fields in cylindrical geometries.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to use Gauss's law and integrate to find the electric field, but expresses confusion about the integration process. Some participants suggest solving Laplace's equation as an alternative approach, while others question the mathematical steps taken, particularly regarding the integration limits and the handling of units.

Discussion Status

The discussion is ongoing, with participants offering different strategies and clarifications. There is no explicit consensus on a single method, but guidance has been provided regarding the integration process and the application of Laplace's equation.

Contextual Notes

Participants note the challenge of the mathematical complexity involved, with some expressing concerns about their mathematical background and seeking simpler approaches. The known voltage of 855 volts is a key constraint in the discussion.

stunner5000pt
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Absolutely stumped here!


A geiger counter has a metal cylinder of 2.10 dimater with a wire stretched along it's axis whose diamtere is 1.34 x 10^-4 cm in dimater. If 855 V is applied between these two what is the electric field at the surface of the wire and the cylinder??

lets say lambda = Q / L

then flux = EA = E 2 pi r L = 4 pi k Qenc = 4 pi k lambda L

so 2 k lambda / r = E

then i integrate because V = integrate E dr

so that V = 2k lambda Log r

But now i m stumped as to how to proceed please help!
thanks a lot
 
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You might try solving Laplace's equation directly since there is no charge in the space between the wire and the cylinder

[tex]\nabla^2 \phi = 0[/tex]

using cylindrical coordinates and making use of your symmetry approximation. (It's easier than it looks!)
 
Tide said:
You might try solving Laplace's equation directly since there is no charge in the space between the wire and the cylinder

[tex]\nabla^2 \phi = 0[/tex]

using cylindrical coordinates and making use of your symmetry approximation. (It's easier than it looks!)

ok thansk a lot BUT I'm not that high in math can u try suggeting a lower math approach?
 
Sorry about that -

You can do it the way you started but you have to careful when you integrate (i.e. the [itex]\ln r[/itex] makes no sense because it can't contain units!)

What you need to do is to integrate from, say, the radius of the inner wire out to a point of interest. To determine the value of the unknown charge you will need to integrate from the radius of the wire all the way out to the radius of the cylinder in which case the potential difference is known to be 855 Volts.

You will end up with something like

[tex]V(r) = \Delta V \frac {\ln r/r_0}{\ln R/r_0}[/tex]

where [itex]r_0[/itex] is the radius of the wire and [itex]R[/itex] is the radius of the cylinder.

Technically, there is an arbitrary additive constant in there but it doesn't matter where you define the zero of the electrical potential since you're going to calculate the derivative to find the electric field.
 

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