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guru
Oct31-04, 01:23 PM
This problem is baffling me.

A 3kg puck revolves in a circle on a frictionless table at the end of a 50cm long string. The puck's angular momentum is 3kg (m^2/s). What is the tension in the string?

This what I did
L= mrv
therefore
3kg*.25m*v = 3kgm^2/2
v=4m/s
F=(mv^2)/r
(3kg*16m/s)/(.25m) = 192N

is this right?

arildno
Oct31-04, 01:49 PM
r should be 0.50 m, not 0.25.

MiGUi
Oct31-04, 02:19 PM
I agree with arildno, the string is acting as the radius of the circle itself, not as the diameter :smile:

Doc Al
Oct31-04, 02:27 PM
Once again: Do not double post!
http://www.physicsforums.com/showthread.php?t=50626