Solving for Tension: 3kg Puck's Angular Momentum on Frictionless Table

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To determine the tension in the string of a 3kg puck revolving on a frictionless table, the angular momentum formula L = mrv is used, leading to a velocity calculation of 4 m/s. The centripetal force required to maintain this motion is calculated using F = (mv^2)/r, resulting in a force of 192N. The calculations confirm that the angular momentum and tension are directly related through the puck's velocity and radius of motion. The derived tension value reflects the necessary force to keep the puck in circular motion. The approach and calculations appear to be correct.
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A 3kg puck revolves in a circle on a frictionless table at the end of a 50cm long string. The puck's angular momentum is 3kg (m^2/s). What is the tension in the string?

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Knowing the angular momentum what can you find? How does this relate to force or tension?
 
Parth Dave said:
Knowing the angular momentum what can you find? How does this relate to force or tension?

L= mrv
therefore
3kg*.25m*v = 3kgm^2/2
v=4m/s
F=(mv^2)/r
(3kg*16m/s)/(.25m) = 192N

is this right?
 
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