Solving for Tension: 3kg Puck's Angular Momentum on Frictionless Table

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SUMMARY

The discussion centers on calculating the tension in a string holding a 3kg puck revolving on a frictionless table. Given the puck's angular momentum of 3kg·m²/s and a radius of 0.5m, the velocity is determined to be 4m/s. Using the formula for centripetal force, the calculated tension in the string is 192N. This conclusion is reached by applying the relationship between angular momentum, velocity, and centripetal force.

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  • Understanding of angular momentum and its formula (L = mrv)
  • Knowledge of centripetal force calculations (F = mv²/r)
  • Familiarity with basic physics concepts related to circular motion
  • Ability to manipulate equations to solve for unknowns
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  • Study the relationship between angular momentum and centripetal force in circular motion
  • Explore the effects of varying mass and radius on tension in similar systems
  • Learn about the conservation of angular momentum in closed systems
  • Investigate real-world applications of tension in rotating systems
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A 3kg puck revolves in a circle on a frictionless table at the end of a 50cm long string. The puck's angular momentum is 3kg (m^2/s). What is the tension in the string?

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Knowing the angular momentum what can you find? How does this relate to force or tension?
 
Parth Dave said:
Knowing the angular momentum what can you find? How does this relate to force or tension?

L= mrv
therefore
3kg*.25m*v = 3kgm^2/2
v=4m/s
F=(mv^2)/r
(3kg*16m/s)/(.25m) = 192N

is this right?
 
Last edited:

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