Angular acceleration with rpms

[ginaoh]

Can someone walk me through this problem?

A power drill reaches 13164 rpm in 1.01 seconds. What is the angular acceleration?

The answer listed is 3.791 rad/s2, but I don't know how to get there.

So far, I did (13164 rev x 2pi)/60 seconds to get 1378.5 rad/s (which is 'w', right)? but change in 'w' from 0-1378.5 / change in 't' from 0-1.01s isn't right.
Please help.

[Doc Al]

The listed answer makes no sense. Are you stating the problem completely?

[ginaoh]

Thanks for responding. I found this problem on a site for practice problems (link listed below). I copied and pasted the question and answer directly from the page. I am confused.


www.dctech.com (http://www.dctech.com/physics/help/tests.php?maketest=yes&selection%5B%5D=circular-acceleration)

[Doc Al]

I went to that site and looked at 3 problems. Only one gave the correct answer; two, gave goofy answers, just like the problem you presented. Forget it. (You may wish to complain to the site owners.)