View Full Version : factor theorem
1. The problem statement, all variables and given/known data
show that (x-2) is a factor of x^3 - 2x^2 + x - 2
2. Relevant equations
3. The attempt at a solution
f(2) = 2^3 - 2(2)^2 + 2 - 2
is that any good
1. The problem statement, all variables and given/known data
show that (x-2) is a factor of x^3 - 2x^2 + x - 2
2. Relevant equations
3. The attempt at a solution
f(2) = 2^3 - 2(2)^2 + 2 - 2
is that any good
What does 2^3 - 2(2)^2 + 2 - 2 simplify to?
what does 2^3 - 2(2)^2 + 2 - 2 simplify to?
= 8 - 8 + 2 - 2
= 0
OK, that's better. Now, you have f(2) = 0, where apparently f(x) = x^3 - 2x^2 + x - 2. If f(a) = 0, what does that tell you about x - a being a factor of f(x)?
OK, that's better. Now, you have f(2) = 0, where apparently f(x) = x^3 - 2x^2 + x - 2. If f(a) = 0, what does that tell you about x - a being a factor of f(x)?
that it is a factor of the equation
that it is a factor of the equation
That x - 2 is a factor of x^3 - 2x^2 + x - 2.
Note that x^3 - 2x^2 + x - 2 is not an equation (there's no equal sign).
That x - 2 is a factor of x^3 - 2x^2 + x - 2.
Note that x^3 - 2x^2 + x - 2 is not an equation (there's no equal sign).
oh ok, got it
NascentOxygen
Aug11-11, 12:00 AM
show that (x-2) is a factor of x^3 - 2x^2 + x - 2
There is nothing stopping you dividing x^3 - 2x^2 + x - 2
by x-2
and showing that there is 0 remainder.
Can you do that? Try it like you'd do long division, where the first "digit" of the answer will be x^2.
x-2 ) x^3 - 2x^2 + x - 2
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