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Candy309
Aug31-11, 06:58 AM
Hi there

I am given xi=x/s(t) and T=h(t)F(xi,t) and I need to tranform deltaT/deltat. How do I do it? Do I use the chain rule? The answer to it is : s*(dh/dt)*F+s*h*(deltaF/deltat)-xi*(ds/dt)*h*(deltaF/deltaxi) but I don't know how to get this answer. Please help me. Thank you

pwsnafu
Aug31-11, 07:36 AM
What's delta T / delta t? Is this from discreet math?

Candy309
Aug31-11, 08:02 AM
Sorry it's \deltaT /\deltat

Candy309
Aug31-11, 08:04 AM
Hi It's the greek letter delta. I want to tranform (delta T)/(delta t)

Candy309
Aug31-11, 08:08 AM
I have to solve a heat equation but first I must change the variables.

Stephen Tashi
Aug31-11, 10:06 AM
I think pwsnafu is asking whether \frac{ \delta T}{\delta t} means the derivative of T with respect to t.

pwsnafu
Aug31-11, 10:09 AM
I think pwsnafu is asking whether \frac{ \delta T}{\delta t} means the derivative of T with respect to t.

Yeah. I've never seen lower case delta used in that way before. Do you mean partial derivative?

Candy309
Aug31-11, 10:12 AM
Yes it is

Candy309
Aug31-11, 10:19 AM
Hi there

I am given xi=x/s(t) and T=h(t)F(xi,t) and I need to tranform deltaT/deltat. How do I do it? Do I use the chain rule? The answer to it is : s*(dh/dt)*F+s*h*(deltaF/deltat)-xi*(ds/dt)*h*(deltaF/deltaxi) but I don't know how to get this answer. Please help me. Thank you

How do you do the change of variable when xi=x-s(t)/1-s(t) and T=(1-s(t))*F(xi,t). I want to transform partial derivative of T with respect to t.

jackmell
Aug31-11, 10:41 AM
Hi there

I am given xi=x/s(t) and T=h(t)F(xi,t) and I need to tranform deltaT/deltat. How do I do it? Do I use the chain rule? The answer to it is : s*(dh/dt)*F+s*h*(deltaF/deltat)-xi*(ds/dt)*h*(deltaF/deltaxi) but I don't know how to get this answer. Please help me. Thank you

That's really messy . . . Candy. Looks like you have a chained list of variables:

\Xi(x,s)=\frac{x}{s}

s=s(t)

T(h,F)=h(t)F(\Xi,t)

and you want to compute:

\frac{dT}{dt}

so by the general chain-rule:

\frac{dT}{dt}=h(t)\frac{\partial}{\partial t} F(\Xi,t)+F\frac{dh}{dt}

and:

\frac{\partial}{\partial t} F(\Xi,t)=\frac{\partial F}{\partial \Xi}\frac{\partial \Xi}{\partial t}+\frac{\partial F}{\partial t}

anyway, doing all that and simplifying, I still don't get exactly what you posted as the answer (close though) so maybe I'm missing something. Maybe though you can clean it up for me.

Candy309
Aug31-11, 10:44 AM
The equation have to transform is d^2T/dx^2=dT/dt