View Full Version : Change of Variables
Candy309
Aug31-11, 06:58 AM
Hi there
I am given xi=x/s(t) and T=h(t)F(xi,t) and I need to tranform deltaT/deltat. How do I do it? Do I use the chain rule? The answer to it is : s*(dh/dt)*F+s*h*(deltaF/deltat)-xi*(ds/dt)*h*(deltaF/deltaxi) but I don't know how to get this answer. Please help me. Thank you
pwsnafu
Aug31-11, 07:36 AM
What's delta T / delta t? Is this from discreet math?
Candy309
Aug31-11, 08:02 AM
Sorry it's \deltaT /\deltat
Candy309
Aug31-11, 08:04 AM
Hi It's the greek letter delta. I want to tranform (delta T)/(delta t)
Candy309
Aug31-11, 08:08 AM
I have to solve a heat equation but first I must change the variables.
Stephen Tashi
Aug31-11, 10:06 AM
I think pwsnafu is asking whether \frac{ \delta T}{\delta t} means the derivative of T with respect to t.
pwsnafu
Aug31-11, 10:09 AM
I think pwsnafu is asking whether \frac{ \delta T}{\delta t} means the derivative of T with respect to t.
Yeah. I've never seen lower case delta used in that way before. Do you mean partial derivative?
Candy309
Aug31-11, 10:12 AM
Yes it is
Candy309
Aug31-11, 10:19 AM
Hi there
I am given xi=x/s(t) and T=h(t)F(xi,t) and I need to tranform deltaT/deltat. How do I do it? Do I use the chain rule? The answer to it is : s*(dh/dt)*F+s*h*(deltaF/deltat)-xi*(ds/dt)*h*(deltaF/deltaxi) but I don't know how to get this answer. Please help me. Thank you
How do you do the change of variable when xi=x-s(t)/1-s(t) and T=(1-s(t))*F(xi,t). I want to transform partial derivative of T with respect to t.
jackmell
Aug31-11, 10:41 AM
Hi there
I am given xi=x/s(t) and T=h(t)F(xi,t) and I need to tranform deltaT/deltat. How do I do it? Do I use the chain rule? The answer to it is : s*(dh/dt)*F+s*h*(deltaF/deltat)-xi*(ds/dt)*h*(deltaF/deltaxi) but I don't know how to get this answer. Please help me. Thank you
That's really messy . . . Candy. Looks like you have a chained list of variables:
\Xi(x,s)=\frac{x}{s}
s=s(t)
T(h,F)=h(t)F(\Xi,t)
and you want to compute:
\frac{dT}{dt}
so by the general chain-rule:
\frac{dT}{dt}=h(t)\frac{\partial}{\partial t} F(\Xi,t)+F\frac{dh}{dt}
and:
\frac{\partial}{\partial t} F(\Xi,t)=\frac{\partial F}{\partial \Xi}\frac{\partial \Xi}{\partial t}+\frac{\partial F}{\partial t}
anyway, doing all that and simplifying, I still don't get exactly what you posted as the answer (close though) so maybe I'm missing something. Maybe though you can clean it up for me.
Candy309
Aug31-11, 10:44 AM
The equation have to transform is d^2T/dx^2=dT/dt
vBulletin® v3.8.7, Copyright ©2000-2012, vBulletin Solutions, Inc.