View Full Version : proof of symmetric and anti symmetric matrices
prawinath
Aug31-11, 10:15 AM
1. The problem statement, all variables and given/known data
aij is a symmetric matrix
bij is a an anti symmetric matrix
prove that aij * bij = 0
2. Relevant equations
aij * bij
3. The attempt at a solution
any one got any ideas ?
Hootenanny
Aug31-11, 11:02 AM
HINT: What happens when you interchange the indices?
Fredrik
Aug31-11, 11:11 AM
a_{ij} doesn't denote a matrix. It denotes the component on row i, column j, of a matrix.
Since \begin{pmatrix}1 & 0 \\ 0 & 1\end{pmatrix}\begin{pmatrix}0 & 1 \\ -1 & 0\end{pmatrix}=\begin{pmatrix}0 & 1 \\ -1 & 0\end{pmatrix}\neq 0, it's not true that the product of a symmetric and an antisymmetric matrix is =0. On the other hand, it is true that a_{ij}b_{ij}=0 (assuming that repeated indices are summed over). You should take some time to think about what the expression a_{ij}b_{ij} really means, and what matrix operation(s) it involves.
Do you know the definition of matrix multiplication? If a_{ij} denotes a component of a matrix A, and b_{ij} denotes a component of a matrix B. Then what will you find on row i, column j of AB?
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