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roldy
Sep29-11, 07:52 AM
It looks like my first post on this did not make it on this forum some how.

I came across this statement.
Even though \frac{N_i}{N}=X_i, \frac{dN_i}{N}\neq dX_i

How does this work? The book offered no help as well as searches on the internet.

Borek
Sep29-11, 02:51 PM
My guess is that as N is sum of all Nk, if Ni changes, denominator changes as well.

roldy
Sep29-11, 02:57 PM
I guess that makes sense. Seems logical to me.

DrStupid
Sep29-11, 03:01 PM
My guess is that as N is sum of all Nk, if Ni changes, denominator changes as well.

Yep, that's it.

dx_i = \frac{{N \cdot dN_i - N_i \cdot dN}}{{N^2 }}

and

dN = dN_i

gives

dx_i = \frac{{N - N_i }}{{N^2 }} \cdot dN_i

But for small x_i

dx_i = \frac{{dN_i }}{N}

is a good approximation.