Physics Problem: Helping My Son Solve a Horizontal Board and Cable Setup

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Homework Help Overview

The problem involves a horizontal board supported by a vertical cable, with weights placed at specific distances from a fulcrum. The goal is to determine the force exerted on the cable due to the weights on the board.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the concept of torque and its application to a balanced lever system. There are questions regarding the choice of pivot point for calculating moments and how this affects the analysis. Some participants express uncertainty about the correct approach to take.

Discussion Status

There is an ongoing exploration of the problem, with some participants providing insights into the calculation of torque and the implications of choosing different pivot points. Guidance has been offered regarding the relevance of the fulcrum's location in simplifying calculations.

Contextual Notes

Participants note that there is flexibility in choosing the pivot point for torque calculations, and that this choice can impact the complexity of the analysis. There is also mention of the need to consider the forces acting on the board and how they relate to the overall balance of the system.

KJT
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will someone please help me help my son with this physics problem?
a board is held horizontal by a cable. the cable is vertical (90degrees to the board). the board is 11 meters long. at the left end of the board is a fulcrum at the right end is the cable. 5 meters from the left end is a weight of 100n and 9 meters from the left end is a weight of 150n. what is the force on the cable.
 
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KJT said:
will someone please help me help my son with this physics problem?
a board is held horizontal by a cable. the cable is vertical (90degrees to the board). the board is 11 meters long. at the left end of the board is a fulcrum at the right end is the cable. 5 meters from the left end is a weight of 100n and 9 meters from the left end is a weight of 150n. what is the force on the cable.

Whenever you have forces acting on a lever you have torque. In this case the lever is balanced, so the net torque is zero.
[itex] \begin{align*}<br /> \tau_{down} & = \tau_{up} \\<br /> (100N)(5m) + (150N)(9m) & = T(11m) \\<br /> T & = 168N<br /> \end{align*}[/itex]
 
Thanks

Thank You For Your Help. I Wasn't Sure Which End Of The Board To Use For Calc The Moment From.
Kjt
 
KJT said:
Thank You For Your Help. I Wasn't Sure Which End Of The Board To Use For Calc The Moment From.
Kjt

To make sure this is very clear, there is NO definite point that you use to calculate the moment. This is entirely by choice! You can even choose a point on the wall or on the ceiling 3 miles away if you want to (very tall ceiling, that is).

However, there certainly is a "proper" choice of where to calculate the moment that will make the calculation a lot easier. This is where the "physics" comes in - knowing where to make the most appropriate choice. It is only when one does problems like this, and does them repeatedly can one get a "feel" for where to put this point.

Zz.
 
KJT said:
Thank You For Your Help. I Wasn't Sure Which End Of The Board To Use For Calc The Moment From.
Kjt

The cable does not provide a torque about the end that the cable is tied to. So, in this case, it would make sense to calculate torques about the other end (or at least, any other point). There's another reason that makes the other end a smart choice : the force exerted by the fulcrum is not known (yet), so calculating moments about a point in line with this force makes the torque due to the fulcrum = 0.

Without saying this in as many words, this was the idea that ZapperZ was trying to convey (I hope).
 

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