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physicsgeek54
Jan2-12, 10:23 AM
I'm having trouble with these two proofs.
cos(n∏+θ)=(-1)^n cos θ
ln|sec x|= -ln|cos x|

I know for the first one that I have to incorporate log somehow but that's about all I got from it.

The1337gamer
Jan2-12, 10:32 AM
For the second one, think about the laws of logarithms you know.

The1337gamer
Jan2-12, 10:36 AM
For the first one i assume the righthandside means ((-1)^n)cos(theta), how can you expand the left hand side, do you know of any identites or formulae?

I'm pretty sure you don't need log for the first one.

Joffan
Jan2-12, 11:28 AM
For the first one, start by thinking about how cos(\pi+\theta) is related to cos(\theta) - the case where n=1

http://www.cliffsnotes.com/study_guide/Addition-Identities.topicArticleId-11658,articleId-11610.html

SammyS
Jan2-12, 11:39 AM
Use the angle addition identity for the cosine: cos(A+B)=cos(A)cos(B)-sin(A)sin(B)