Potential Due to collection of point charges

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Homework Help Overview

The discussion revolves around calculating the electric potential at a point due to an infinite series of point charges located along the x-axis. The charges are all positive and have a value of 8.0 C, with their positions defined by a geometric progression based on a specified distance a.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply the formula for electric potential but expresses confusion regarding the results they are obtaining. Some participants question the formulation of the problem and suggest expressing the answer in terms of variables rather than numerical values. Others provide hints about summing series and evaluating limits without revealing complete solutions.

Discussion Status

The discussion is ongoing, with participants providing guidance on how to approach the summation of the potentials from the individual charges. There is a mix of encouragement for the original poster to continue working through the problem and reminders to avoid giving away complete answers.

Contextual Notes

There is a mention of a potential typo in one of the posts, indicating that clarity in communication is important. The original poster's confusion about the numerical results suggests that there may be assumptions or steps in the problem that need further exploration.

GingerBread27
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As shown below, an infinite number of point positive charges of 8.0 C are placed on the x-axis at x=a, 2a, 4a, 8a, ... with a=18 cm. Find the electric potential (in V) at the point x=0.

0---a----2a---4a-----8a-------

Ok so I'm using the equation V=1/(4piEpsilon)Sigma(q/r). and it's not working! I don't understand what I'm doing wrong it should be pretty easy. Please help. I'm using 8 Coulombs as my q and r is my changing variable. I'm getting 88.88 and it's not working.
 
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your method is fine... what is your answer in term of V,q,a...etc? (not the numerical value )
the following equation might help you
[tex]\sum_{x=0}^\infty \frac{1}{2^x} = 2[/tex]
 
Last edited:
Your total potential is just the sum of all the separate potentials, so:
[tex]V(0) = \frac{Q}{4\pi\epsilon_0} \sum_{i=0}^\infty \frac{1}{2^i a}[/tex]

Now try to evaluate this sum and you'll get your answer :rolleyes:
 
Last edited:
-blah- stupid
 
sory, typo
please don't give out the answer...
leave some work for the OP to do
 

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