Calculating Time for Cockroaches to Meet with Different Accelerations

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SUMMARY

The problem involves calculating the time it takes for two cockroaches, starting 60 cm apart, to meet while accelerating towards each other. The first cockroach accelerates at 0.20 m/s², while the second accelerates at 0.12 m/s². Using the kinematic equation x = x₀ + v₀t + (1/2)at², the total distance covered by both cockroaches is set to 60 cm. The solution reveals that the time taken for the cockroaches to meet is approximately 19.36 seconds.

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chonny
Please help me...I've been struggling for a long time over this following problem...

Some cockroaches can run as fast as 1.5 m/s. Suppose that two cockroaches are separated by a distance of 60 cm and that they begin to run toward each other at the same moment. Both insects have constant acceleration until they meet. The first cockroach has an acceleration of 0.20 m/s^2 in one direction and the second one has an acceleration of 0.12 m/s^2 in the opposite direction. How much time passes before the two insects bump into each other?


Please give me the answer and the steps leading to the answer as soon as possible...I am most grateful :wink:

If not...I will kill myself
 
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a_1=0.2
a_2=0.12
v_01=v_02=0
x=x_0+v_0*t+at^2/2
x_1=0+0+a_1*t^2/2=0.2*t^2/2
x_2=0+0+a_2*t^2/2=0.12*t^2/2
x_1+x_2=60
0.2*t^2/2+0.12*t^2/2=60
t=19.36 sec


p.s
dont kill yourself :smile:
 
thank you ...*puts down shotgun*
 

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