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mugzieee
Feb16-05, 02:14 AM
i got a problem that says:
x=sqrt(5)sin2t -2
y=sqrt(5)cos2t - sqrt(3)

how would i go about starting it?

Justin Lazear
Feb16-05, 02:27 AM
Do you know the equation for arc length for a parameterized curve?

--J

dextercioby
Feb16-05, 02:52 AM
One other thing:You may wanna know between which points you wish to compute the length...?In other words,give 2 distinct values of "t"...The integral doesn't seem to be difficult...

Daniel.

xanthym
Feb16-05, 03:29 AM
i got a problem that says:
x=sqrt(5)sin2t -2
y=sqrt(5)cos2t - sqrt(3)

how would i go about starting it?
:(1): \ \ \ \ (CurveLength_{t=a}^{t=b}) = \int_{a}^{b} \sqrt { (\frac {dy} {dt})^2 + (\frac {dx} {dt})^2} \ \ dt

(HINT: If solved correctly, this problem simplifies very rapidly!!)


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