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Matty9879
Mar9-05, 09:40 PM
Cant quite get this one.
What I think is that I3 and I1 add together to get I2
and I found this equation V1+v2=E1-E2 and V3+V2=E3-E2 and I was substituting IR in for all the V's and I3+I1 where I2 comes in and making two equaitons and solving but no dice any tips? Thanks.
_________/\R3\/l
l l I3-> l
E1 ^ E2 E3 R1 = 1.00 kΩ, R2 = 2.00 kΩ, R3 = 3.00 kΩ,
l l R3 l E1=60.0V, E2 = 45.0 V and E3 = 70.0 V
l I2 l l ok the e's are epslons V=IR epslon subs in for V
l l l I did the best I could to show current direction
l l l It was tough to draw let me know if your confused
---/\R1/\-------l Or if you kn know a better way to draw on this
I1->

Gamma
Mar9-05, 09:52 PM
I found this equation V1+v2=E1-E2 and V3+V2=E3-E2 and

Check your signs. v1+v2 = E2 - E1 and v3+v2 = E2-E3

Matty9879
Mar10-05, 07:41 AM
ok i kind of see how you get that but thats not my problem my problem is finding which currents to use where