Average Induced EMF in Loop of Wire Rotated in B-Field

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SUMMARY

The average induced electromotive force (emf) in a 7.2 cm diameter loop of wire rotated in a 1.3 T magnetic field is calculated to be 2.6E-2 V. The area of the loop is determined using the formula A = πr², resulting in an area of 0.004 m². The magnetic flux (ФB) is computed as ФB = BA, yielding 5.2E-3 Wb. The discussion highlights the importance of considering the angle between the magnetic field and the loop's plane, suggesting the use of the dot product to account for changes in orientation.

PREREQUISITES
  • Understanding of Faraday's Law of Electromagnetic Induction
  • Familiarity with magnetic flux calculations
  • Knowledge of the area of a circle formula (A = πr²)
  • Basic concepts of vector mathematics, particularly dot products
NEXT STEPS
  • Study the application of Faraday's Law in different geometries
  • Learn about the effects of angular velocity on induced emf
  • Explore the derivation and application of the root mean square voltage in AC circuits
  • Research the implications of changing magnetic fields on induced currents
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Physics students, electrical engineers, and educators looking to deepen their understanding of electromagnetic induction and its applications in rotating systems.

airkapp
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A 7.2 cm diameter loop of wire is initially oriented perpendicular to a 1.3 T magnetic field. It is rotated so that its plane is parallel to the field direction in .20 s. What is the average induced emf in the loop?

A = πr2

A = π*.001 = .004 m

ФB = BA

= (1.3T)(.004m) = 5.2E-3 Wb

ФB / t = 0-5.2E-3 Wb / .20 s

= -2.6E-2 Wb/s

€ = -(1)( -2.6E-2 Wb/s)

= 2.6E-2 V


I think i messed up in my area of my formula. can someone help me out here.
 
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I don't see any trig functions there... because the loop is rotated, there has to be a change in the dot product of the vectors.

Remember that A . B = |A| |B| cos theta
 
Now that I think about it - can't you just take BA/t and then times it by 1/root(2) to get the root mean square voltage.
 

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