How Far Apart Are Two Adjacent Nodes in a Standing Wave?

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Homework Help Overview

The discussion centers around the calculation of the distance between adjacent nodes in a standing wave, given the wave's velocity and frequency. The original poster presents a calculation of the wavelength and expresses confusion regarding the relationship between the wavelength and the distance between nodes.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between wavelength and the distance between nodes, with some questioning the need to divide the wavelength by two to find the distance between adjacent nodes. The original poster seeks clarification on the implications of the problem statement regarding harmonic waves.

Discussion Status

Some participants provide insights into the nature of nodes in standing waves and the reasoning behind the calculations. There is an ongoing exploration of the definitions and assumptions related to standing waves, with no explicit consensus reached on the interpretation of the problem.

Contextual Notes

The problem is noted to be ambiguous, as it does not specify the characteristics of the waves beyond identifying them as standing waves. This raises questions about the assumptions that can be made regarding their periodicity and sinusoidal nature.

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The velocity of waves on a string is 92 m/s. If the frequency of standing waves is 475Hz, how far apart are two adjacent nodes?

W = wavelength

f = v/W


W = 92/475 = 0.194 m

At this stage, I thought the answer was sufficient. However, maybe it is because i don't udnerstand the question, but the book says the answer should be 0.097m. The only way I could achieve this was to:

L = W/2 = 0.194 / 2 = 0.097m

This should then be a first harmonic wave. I am wondering:

Isnt the distance bewteen two adjacent nodes simply the wavelength?
Why should I divide it by 2, and when does the question imply it is talking about a first harmonic wave?

Thank you
 
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A node is a point where there is no displacement. Just look at the sine wave, it has two zero's in one period, so there are two nodes in a wavelength.
 
ah i see! Thx!
 
Link are you all set now or are you still wondering why the length between the nodes is not the wave length?

Kitty
 
The problem is rather ambiguous.It says nothing about the appearance of those waves.They need't be periodic,nor sinusoidal,just solutions of the d'Alembert equation.

Daniel.
 
Well not really. It says it is a standing wave, must have to fixed points. I says what the frequency of that wave is and what speed the wave is traveling at. This means the wavelength can be worked out and in all standing waves (of the sort Link's mentions) you then divide by two to find the distance between the nodes.

The Bob (2004 ©)
 
The answer given is correct it's= 0.09684m
The wave length of a standing wave is equal to (distance between the two nodes*2)

Think how standing waves are made (by interference of two periodic waves).then you would be able to figure thi out.note that node is the place where the pressure is highest and that there are two such places in a beat.
 
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.../...\.....
../...\......
/...\....
...\.../...
....\.../...
......\.../...
.....V...

Your standing wave - the distance between the nodes, is either one peak or one trough as above - aka half a wavelength.


Just wanted to use some ASCII art there to clarify the point some :-)


EDIT:::
Sorry had to add dots as ASCII spaces were removed
 
Last edited:

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