How to Find Final Temperature in a Calorimetry Copper Pot Problem?

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SUMMARY

The discussion focuses on solving a calorimetry problem involving a copper pot, water, and an iron block. The equation used is Qwater + Qiron + Qcopper = 0, where Q represents heat transfer. The specific heat capacities and masses of the materials are crucial for calculating the final temperature. The final temperature can be determined by rearranging the equation to isolate Tfinal, using the formula m*c*(Tfinal - Tinitial) for each component.

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  • Understanding of calorimetry principles
  • Knowledge of specific heat capacities for copper, water, and iron
  • Ability to manipulate algebraic equations
  • Familiarity with the concept of thermal equilibrium
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  • Research specific heat capacities of copper, water, and iron
  • Learn how to apply the conservation of energy principle in calorimetry
  • Study algebraic techniques for solving equations with multiple variables
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ziddy83
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Hey what's up,
I am stuck on the following problem.

a copper pot with mass of 0.5kg contains 0.170kg of water at a temperature of 20C. A 0.250kg block of iron at 85C is dropped into the pot. Find the final temperature assuming not heat loss.

Ok, so Here is what i was thinking about doing:

Qwater + Qiron + Qcopper = 0

i know the initial temperature of the system, 20C. i also know the temp of the Iron block. so...How do i find the final T? Q = mc(Delta T), the delta T part is where I am confused. How do i set up the equation so i can solve for Tfinal? Thanks for any help.
 
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Your equation is set up correctly.

[tex]\Delta T = T_{final} - T_{initial}[/tex]

Just use the idea of

[tex]m_{copper}c_{copper}(T_{final} - T_{initial copper}) + m_{water}c_{water}(T_{final} - T_{initial water}) + m_{iron}c_{iron}(T_{final} - T_{initial iron}) = 0[/tex]

Use Distributive of product with respect to addition property, then factor the T final.
 
Sweet...thanks a lot man.
 

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