Calculate Energy Released in 2/1H + 3/1H -> 4/2He + 1/0n Reaction

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The forum discussion focuses on calculating the energy released in the nuclear reaction 2/1H + 3/1H -> 4/2He + 1/0n. Participants emphasize the importance of determining the mass defect by finding the difference in mass between the reactants and products. The conversion of this mass difference into energy is achieved by multiplying the result by 931 MeV/amu. This method provides a clear pathway to quantify the energy released in nuclear reactions.

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  • Nuclear reaction equations
  • Mass defect calculation
  • Energy-mass equivalence (E=mc²)
  • Understanding of atomic mass units (amu)
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whiteshado
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Calculate the energy (in Mev's) released in the reaction: 2/1H + 3/1H ->4/2He + 1/0n + E
and i know 1 amu = 931 Mev
 
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Calculate the difference in mass between the reactants and the products, then convert that mass difference into energy units.

- Warren
 
Either the book where u've taken that reaction or the internet has to have the rest masses of those 4 partices.

Daniel.

P.S.Evaluate the mass defect in amu-s and then simply multiply the result by 931MeV/amu.
 

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