Problem in graph of Quadratic Equation

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SUMMARY

The graph of a quadratic equation, represented as ax² + bx + c, is symmetric due to its parabolic shape, with the vertex located at the point (-b/2a, f(-b/2a)). The value of 'a' in the equation determines the direction and width of the parabola; if 'a' is positive, the parabola opens upwards (dale-parabola), and if negative, it opens downwards (hill-parabola). The vertex also represents the maximum or minimum point of the graph, confirming that -b/2a is the mean of the two roots.

PREREQUISITES
  • Understanding of quadratic equations and their standard form
  • Familiarity with the concept of symmetry in mathematical graphs
  • Knowledge of vertex form of quadratic equations
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the properties of quadratic functions and their graphs
  • Learn about the vertex form of quadratic equations
  • Explore the significance of the discriminant in determining the nature of roots
  • Investigate transformations of quadratic functions, including vertical and horizontal shifts
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Students learning algebra, educators teaching quadratic equations, and anyone interested in understanding the graphical representation of quadratic functions.

Neha Sanghvi
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Hey, could someone please help me with this problem? I just want to know why the graph of Quadratic Equation are symmetric and why does the maxima and minima ( = -b/2a ) the mean of the two roots? One more thing I didn't get was what does the a represent in ax2+bx+c ( ax square+bx+c)? I know for b and c, but couldn't figure out for a? Is it for the slope or whether the graph will be > 0 or < 0?
 
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If you write [itex]ax^2+bx+c[/itex] in the more 'insightful' form:

[tex]a\left(x+\frac{b}{2a}\right)^2+\left(c-\frac{b^2}{4a}\right)[/tex]

You can see that it is equal to the graph of [itex]ax^2[/itex], but shifted vertically by [itex]c-\frac{b^2}{4a}[/itex] and horizontally by [itex]\frac{b}{2a}[/itex]. The a can be seen as a scaling factor in the y-direction. If it's positive, you have a 'dale-parabola', if it's negative it's a 'hill-parabola'.
 

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