Where Can I Study Peskin and Schroeder? | Physics Forums

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Homework Help Overview

The discussion revolves around the study of Peskin and Schroeder, particularly in the context of quantum field theory. Participants are exploring the relevance and understanding of specific expressions and calculations related to the text.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to clarify the meaning of certain mathematical expressions and their implications in quantum field theory. Questions about the lack of responses and the appropriateness of the original inquiry are also raised.

Discussion Status

Some participants are engaging with the mathematical content, while others express concern about the lack of replies to their questions. There is an ongoing exploration of the interpretations of the expressions discussed, with no clear consensus yet.

Contextual Notes

Participants are navigating through complex concepts and may be facing challenges in understanding the material. There is an indication of a need for further clarification on specific points raised in the discussion.

Neitrino
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Sorry but,

Could at least tell me why my question is not getting any replies?
Im very wondered... its too nonsensical :confused: ? If so what do I say wrong?
 
I think the expresion [tex]<0|\phi(x)\phi(y)|0>[/tex]
survives [tex]<0|a_p a_q^\dag|0>[/tex] means:
[tex]<0|a_p^\dag a_q^\dag|0>[/tex]=0 and [tex]<0|a_p a_q|0>[/tex]=0;
only [tex]<0|a_p a_q^\dag|0>[/tex] survives, of course p and q are arbitary,
not single p and single q. the final result will be an integral over all possible p or q.

(2) [tex]<0|\phi(x)|[/tex], is just complex conjugate of (2.41).
there is no special physical significance here, the author, I guess, just mentioned NR
case to make the formula be easily understood.
 
Last edited:
snooper007 said:
[tex]<0|\phi(x)=<x|[/tex] this is a simple calculation
(as u posted in homework section)

Dear Snooper007 thks for ur reply..
[tex]<0|\phi(x)[/tex] it is a complex conjugation of [tex]\phi(x)|0>[/tex]
So [tex]<0|\phi(x)=\int{\frac{d^3 p}{(2\pi)^3}\frac{1}{2E_p}e^{ipx}<p|[/tex]

[tex]<0|\phi(x)=<x|[/tex] < - ?

and with regard to question 1) I still don't feel comfort with understanding..
seems I did no understand ur reply as it should be
 
I wonder in what colleges one studies Peskin and Schroeder...
 

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