One question on cercular motion

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The discussion centers on calculating the centripetal acceleration and the forces involved for a car rounding a curve. The car has a mass of 13750 N and travels at a speed of 47.0 km/h on a curve with a radius of 260 m. The correct formula for centripetal acceleration is a = v² / R, leading to a calculated centripetal acceleration of 0.66 m/s². The minimum coefficient of static friction required for safe navigation of the curve is determined to be 0.067.

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just need to know what to do i keep getting different answers


[SFHS99 7.P.44.] A 13750 N car traveling at 47.0 km/h rounds a curve of radius 2.60 102 m.

(a) Find the centripetal acceleration of the car.


.66 m/s sqaured


(b) Find the force that maintains centripetal acceleration.
<this is what i can't get right here is what i got please tell me what to do>

N

9014.18

9006.38

1403.06

those are the answers i got can someone please tell me the right answer and how to get it that's a lot and equation would be nice i have been using

ma = ma(v^2)/R

(c) Find the minimum coefficient of static friction between the tires and the road that will allow the car to round the curve safely

.067 = coef.


thanks
 
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The equation you're using has a typo.
It's supposed to be ma = mv2 / R (without that extra a).

a) I got a different answer (R = 102m, if I understood the numbers right?)
b) and c) Could you show what you've tried, and why?
 

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