Angular acceleration of a skater

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Homework Help Overview

The problem involves calculating the angular deceleration of a skater performing a pirouette, transitioning from a rate of 2.0 revolutions per second to a stop over a distance of 3/4 of a revolution. The original poster expresses confusion regarding their calculated value of angular deceleration compared to the textbook's value.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of a specific formula relating angular velocity and angular displacement to find angular acceleration. Questions are raised about the original poster's calculations and the formulas used.

Discussion Status

The discussion is active, with participants seeking clarification on the formulas and calculations involved. There is acknowledgment of rounding in the textbook's answer, but no consensus on the correctness of the original poster's calculation.

Contextual Notes

Participants note the assumption of constant angular deceleration and the potential for rounding differences in the results. The original poster's calculation appears to differ from the expected textbook answer.

brad sue
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Hi,
I need help with the following problem.

A skater does a pirouette at the rate of 2.0 rev / second and then stop within 3/4 rev. Assume that the angular decceleration is constant and calculate its magnitude.

I tried to compute it but I found -18 rad/s2.
BUt the textbook gives -17 rad/s2.
Please can someone help me with this problem?

Thank you
B
 
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brad sue,
use
[tex]\omega^2 \ = \ {\omega^2}_o \ + \ 2\alpha \ \Delta\theta[/tex]
The rotational equivalent of
[tex]v^2 \ = \ {v^2}_o \ + \ 2as[/tex]
 
Last edited:
What formula did you use to compute 18 rad/s2?

What is the angular analogy to v2 = vo2 + 2ax?

The 17 rad/s would be rounded.
 
Astronuc said:
What formula did you use to compute 18 rad/s2?
What is the angular analogy to v2 = vo2 + 2ax?
The 17 rad/s would be rounded.

Yes the -17 has been rounded.
Thank you very much you all..

B
 

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