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 c299792458 Jan24-13 06:37 PM

Killing vector

Let us denote by $X^i=(1,\vec 0)$ the Killing vector and by $u^i(s)$ a tangent vector of a geodesic, where $s$ is some affine parameter.

What physical significance do the scalar quantity $X_iu^i$ and its conservation hold? If any...? I have seen this in may books and exam questions. I wonder what it means...

 WannabeNewton Jan24-13 06:57 PM

Re: Killing vector

Hi there! The point is that the scalar quantity you formed is constant along the geodesic! Using your notation, $\triangledown _{U}(X_{i}U^{i}) = U^{j}\triangledown _{j}(X_{i}U^{i}) = U^{j}U^{i}\triangledown _{j}X_{i} + X_{i}U^{j}\triangledown _{j}U^{i}$. Note that $U^{j}U^{i}\triangledown _{j}X_{i}$ vanishes because $U^{j}U^{i}$ is symmetric in the two indices whereas, by definition of a killing vector, $\triangledown _{j}X_{i}$ is anti - symmetric in the two indices and it is very easy to show that the contraction of a symmetric tensor with an anti - symmetric one will vanish. The second term $X_{i}U^{j}\triangledown _{j}U^{i}$ vanishes simply because U is the tangent vector to a geodesic thus we have that $\triangledown _{U}(X_{i}U^{i}) = 0$. In particular note that if this geodesic is the worldline of some freely falling massive particle then its 4 - velocity is the tangent vector to the worldline and we can re - express the condition for the worldline being a geodesic in terms of the 4 - momentum of the particle (and for photons just define the geodesic condition like this) and we can have that if $X^{i}$ is a killing field on the space - time then $X_{i}P^{i}$ will be constant along this geodesic. It is a geometric way of expressing local conservation of components of the 4 - momentum; these killing fields are differentiable symmetries of the space - time and you might be able to see that more clearly by the fact that the lie derivative of the metric tensor along the killing field will vanish.

 jfy4 Jan24-13 10:50 PM

Re: Killing vector

dat signature...

 WannabeNewton Jan24-13 11:02 PM

Re: Killing vector

Quote:
 Quote by jfy4 (Post 4242009) dat signature...
:[ don't judge me T_T

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