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NateTG
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#8
Feb12-04, 10:30 AM
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Originally posted by loop quantum gravity
i didnt think about it very much so perhaps from this had risen the misunderstanding.
i guess in the real numbers is really trivial.
so lets say just prooving for integers how do you go around prooving this?
[x,y]=[Z] or [x,x/(x-1)]=[Z]
For [tex]\frac{x}{x-1}[/tex] to be an integer, [tex]x-1[/tex] must divide[tex]x[/tex]. Since the difference between the two is 1, their greatest common factor is 1, so the only solutions are [tex]x-1=1[/tex] and [tex]x-1=-1[/tex] (2+2=2*2 and 0+0=0*0).