Quote by craka
1. The problem statement, all variables and given/known data
Question states "The plane that contains the line r=<2,4,3>+t<3,21> and is perpendicular to the plane r=<5,0,0>+s<2,1,0>+t<1,0,1> is:"
Answer is y+2z=10
2. Relevant equations
Cross product and dot product of vectors
3. The attempt at a solution
I found a vector normal to the plane r=<5,0,0>=s<2,1,0>+t<1,0,1>
by doing the cross product of the two direction vectors is <2,1,0> x <1,0,1>
getting <1,2,1>
than apply rule of n.v=0 ie <1,2,1> . <x(2), y4, z3>
to get x+22y+8+z3=0
and so x2y+z = 7
Not sure what I have done wrong here, could someone explain please?
