Quote by Office_Shredder
For the first one, try dividing the numerator and denominator by [tex]3^n[/tex], and see if you can get an idea for what the numerator and denominator look like when n is large

[tex]lim_{n\rightarrow\infty}\frac{\frac{2}{3^{n}}+3}{\frac{2n+2}{3^{n}}+n+1 } = \frac{3}{\infty+1} = 0
[/tex]
I believe I'm getting tired,
missed a whole point here.
Thanks a lot for help.