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cpyap
cpyap is offline
#3
Sep2-10, 02:43 PM
P: 13
Quote Quote by Office_Shredder View Post
For the first one, try dividing the numerator and denominator by [tex]3^n[/tex], and see if you can get an idea for what the numerator and denominator look like when n is large
[tex]lim_{n\rightarrow\infty}\frac{\frac{2}{3^{n}}+3}{\frac{2n+2}{3^{n}}+n+1 } = \frac{3}{\infty+1} = 0
[/tex]
I believe I'm getting tired,
missed a whole point here.
Thanks a lot for help.