Integrating Factor, how do you get this?

HallsofIvy

As I said, they didn't "drop" mu, they solved for it!
If
[tex]\frac{du}{dx}= F(x)u[/tex]
then
[tex]\frac{du}{u}= F(x)dx[/tex]
and, integrating both sides,
[tex]ln(u)= \int F(x)dx[/tex]

Now take the exponential of both sides.

HallsofIvy Recognitions: Gold Member Science Advisor Staff Emeritus	Integrating Factor, how do you get this? As I said, they didn't "drop" mu, they solved for it! If [tex]\frac{du}{dx}= F(x)u[/tex] then [tex]\frac{du}{u}= F(x)dx[/tex] and, integrating both sides, [tex]ln(u)= \int F(x)dx[/tex] Now take the exponential of both sides.