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P: 6,275
 Quote by edgepflow The energy required is the mass of water multiplied by the laten heat of vaporization: Q = m $h_{fg}$ Q = energy required m = mass of water $h_{fg}$ = latent heat of vaporization If you want to estimate how long it will take to evaporate naturally, search for "swimming pool evaporation equation."
No, he said it starts off at 75 degrees. Surely that has to be taken into account. I mean, it CAN'T take the same amount of energy to evaporate water at 1 degree above freezing as to do it to water at 1 degree below boiling.