 Quote by edgepflow
The energy required is the mass of water multiplied by the laten heat of vaporization:
Q = m [itex]h_{fg}[/itex]
Q = energy required
m = mass of water
[itex]h_{fg}[/itex] = latent heat of vaporization
If you want to estimate how long it will take to evaporate naturally, search for "swimming pool evaporation equation."
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No, he said it starts off at 75 degrees. Surely that has to be taken into account. I mean, it CAN'T take the same amount of energy to evaporate water at 1 degree above freezing as to do it to water at 1 degree below boiling.