Thanks for the replies everyone, but I'm still not seeing it. I am not trying to copy and paste an answer here, I'm doing this on my own time, trying to study before I go back to school in the Fall.
Where does the e come from? Is there some basic calculus that I'm overlooking? It looks to me that solving the problem should go something like this:
[itex]\frac{dv}{dt}[/itex]= g  kv
∫[itex]^{t}_{0}[/itex]dvdt = ∫[itex]^{t}_{0}[/itex](g  kvt)dt
v = gt  kvt → v = [itex]\frac{gt}{1 + kt}[/itex]
Which makes sense, but doesn't match the answer in the book. Is the book incorrect, or am I? What am I missing here?
Thanks again for the help everyone.
Merb
