One chain-link pulls another
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Feb26-12, 07:59 AM
Nah, it's not 15 N, it's the acceleration of (B+C)
Oh I see, sorry.
The net force acting on B+C is the vector sum of the tension in the mid string (answer required) and the weight of B+C, and this net force = ma = (0.2+0.2)(15)
You should get the correct answer by now.