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Nov27-04, 01:42 PM
Sci Advisor
PF Gold
chem_tr's Avatar
P: 613
You need help, my friend

First, prepare atomic-based electron balance:

[tex]N^{2+} \longrightarrow N^{5+} + 3e^-[/tex]
[tex]Mn^{7+}+5e^- \longrightarrow Mn^{2+}[/tex]

Then balance them.

[tex]5N^{2+}+3Mn^{7+}\longrightarrow 5N^{5+}+3Mn^{2+}[/tex]

You'll see that both electron counts and atom counts are balanced now.

When you write the "real" ions, I mean, NO and MnO4-, you'll have to add OH- and H2O to the side with less oxygen and less hydrogen, etc.