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courtrigrad
courtrigrad is offline
#2
Feb8-05, 07:04 PM
P: 1,239
ok so the question is that we want to determine the larger angle [tex] \alpha [/tex] in the range [tex] \pi < \alpha < 2\pi [/tex]

Now [tex] \sec x = \frac{1}{\cos x} [/tex] See if you can go from here.