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lurflurf
#16
Sep1-05, 04:40 AM
HW Helper
P: 2,263
Quote Quote by traianus
Thank you for your answer. The function I have is delta (t-u), which is similar (in concept) to the function delta(t). The function delta(t) is infinite when t = 0. So I deduce that delta (t-u) is infinite when t-u=0. Right? If so something does not work. Please convince me!
t is never zero in delta(t-t+) the t+ means we always chose a number larger than t. Thus we always get zero. It is like delta(0+) we chose a number larger than zero (but in a limit process ever closer to zero) thus we always get zero.
delta(0+)=0
delta(t-t+)=0
this is much like the nonsingular case define
f(x)=0 x!=0(x not zero)
f(x)=1 x=0
f(0+)=0
Limits care about the journey not the destination. The whole point of using limits is to find out what happen as we approch a value when we do not like or do not care about what happens at the value.