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A puzzle of two scalar dynamics |
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| Sep8-11, 12:30 AM | #1 |
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A puzzle of two scalar dynamics
I have a puzzle when I study the hybrid inflation model.
Suppose we have two scalar fields, [itex]\phi_1 and \phi_2[/itex] first, lets consider the situation where they are in their independent potentials [itex]V(\phi_i)=m_i^2\phi_i^2, i = 1,2[/itex] with initial value [itex]\phi_i^{ini}[/itex] We can solve the scalar dynamic equations for them. And they are both in harmonic oscillation. This is Okay. But when a 'mixing term' [itex]\lambda^2 \phi_1\phi_2[/itex] is introduced, [itex]\phi_1[/itex] and [itex]\phi_2[/itex] get infinite values, if \lambda is large. This can be showed numerically. What I thought is the large mixing term would lead to [itex]\phi_1 = \phi_2[/itex]. So why it goes to infinite? And we can rotate [itex]\phi_1[/itex] and [itex]\phi_2[/itex] to a basis where there is no mixing term. In this basis, we would not get infinite values for [itex]\phi_1[/itex] or [itex]\phi_2[/itex]. So it seems I get a different result working in different basis. What is the problem |
| Sep8-11, 01:00 AM | #2 |
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You are confusing scalar quantities with vector quantities.
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| Sep9-11, 04:19 AM | #3 |
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Recognitions:
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| Sep14-11, 08:51 AM | #4 |
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A puzzle of two scalar dynamics |
| Sep14-11, 08:59 AM | #5 |
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| Sep14-11, 10:12 AM | #6 |
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Recognitions:
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If your cross term is zero, then the mixing matrix is diagonal, and the particles we observe are the fundamental particles. If, however, the mixing term is at the limit [itex]\lambda^2 = m_1^2 + m_2^2[/itex], then the mixing matrix is saying that there are is in actuality only one fundamental particle that is mixed into these two, and the behavior of the system is fully-specified by the behavior of one of the particles. If you try to get larger off-diagonal terms, the mixing matrix ceases to make any sort of physical sense. |
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