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Calculate work needed to evaporate water 
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#1
Oct2311, 12:32 AM

P: 3

how would you calculate the work needed to evaporate water from washed clothes, if the clothes r in a well isolated room with temperature of 75F
help plzzzz 


#2
Oct2311, 11:13 AM

P: 688

The energy required is the mass of water multiplied by the laten heat of vaporization:
Q = m [itex]h_{fg}[/itex] Q = energy required m = mass of water [itex]h_{fg}[/itex] = latent heat of vaporization If you want to estimate how long it will take to evaporate naturally, search for "swimming pool evaporation equation." 


#3
Oct2311, 11:20 AM

PF Gold
P: 6,072




#4
Oct2311, 01:46 PM

P: 688

Calculate work needed to evaporate water
q = m [itex]h_{fg}[/itex] + m [itex]c_{p}[/itex][itex] \Delta[/itex]T cp = specific heat [itex]\Delta[/itex]T = temperature change = 212 F  75F 


#5
Oct2311, 05:14 PM

P: 3

thank you for the reply guys, see what im trying to do is actually calculate how much money would u save from line drying clothes vs using an electric dryer. knowing that u have an ac/ heater at the houseto keep the temperature at 75. so i was thinking that after calculating the heat to evaporate the water from the clothes wouldnt be the same amount of energy that the ac/heater has to apply to maintain the temperature at 75?



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