## Ti89 Titanium "too few arguments"

sorry for my noobieness, but I'm having problem with my mod( function on my Ti89 Titanium

On other calcs: 54 mod 10 = 4

But when i use the mod( function I either get "to few arguments" og just the result 54.mod10

can anyone point me to what I'm doing wrong?
 PhysOrg.com science news on PhysOrg.com >> A robot that runs like a cat (w/ Video)>> Global cooling as significant as global warming, research shows>> 'Chase and run' cell movement mechanism explains process of metastasis
 Recognitions: Homework Help Welcome to PF, Spagnum! Have you tried mod(54,10)?
 Thank you! yes I have - that just results in "Too few arguments"

Recognitions:
Homework Help

## Ti89 Titanium "too few arguments"

 Quote by Spagnum Thank you! yes I have - that just results in "Too few arguments"
Ah well, I do not own a Ti89, but this page: http://www.prenhall.com/esm/app/grap...nu/number.html
shows that mod(-5,8) --> 3 should work, complete with screenshot.
 Yup I been to that page myself but I get the same result.(Too few arguments) I even reset the calculator, in case it had something to do with some settings.

Recognitions:
Homework Help
 Quote by Spagnum Yup I been to that page myself but I get the same result.(Too few arguments) I even reset the calculator, in case it had something to do with some settings.
The one reason I can think it might say "too few arguments", is if there's a problem with the decimal point, in which case you'd have tried to calculate mod(54.10, ???)
You sure you used a comma?
Or perhaps you could try a semicolon?
 ofc... the comma. I'm so use to working in Excel where . is the comma, and haven't used my calculator in ages. Anyways it works like a charm now, thanks a lot for your help Serena!
 Admin On my TI-89 (but not Titanium) mod(54,10) gives correct 4.
 Mentor The old UK versus USA, comma versus period switcheroo, eh?
 Recognitions: Homework Help Uhh I've never heard of using a period as an argument separator?
 Hey I am also a noob and I need help. I made this program to calculate the area of a sector and I keep getting "Too Few Arguments" The ø is a theta and the 'arrow' is the arrow made by STO area_sec() Prgm Local a,r,g,s,ø,k Dialog Request "Press 1 if you have rs and 2 if you have rø"a EndDlog If a=1 Then Dialog Request "Enter r",r Request "Enter s",s EndDlog expr(-r) 'arrow' r expr(s) 'arrow' s (1/2)*r*s 'arrow' k Disp "Area is"&string(k) Else If a=2 Then Dialog Request "Enter r",r Request "Enter ø",ø Dialog expr(-r) 'arrow' r expr(s) 'arrow' s (1/2)*r*r*ø 'arrow' k Disp "Area is"&string(k) Else EndIf DelVar a,r,s,ø,k EndPrgm

Look at line 5 again:

 Request "Press 1 if you have rs and 2 if you have rø"a
You forgot a comma in between your "request" and your variable, like so:

Code:
Request "Press 1 if you have rs and 2 if you have rø",a
Try that and see what you get.

 Similar Threads for: Ti89 Titanium "too few arguments" Thread Forum Replies Calculators 204 Calculators 1 Calculators 3 Materials & Chemical Engineering 0 Calculators 16