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Finding a subspace (possibly intersection of subspace?) |
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| Nov5-11, 05:31 PM | #1 |
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Finding a subspace (possibly intersection of subspace?)
1. The problem statement, all variables and given/known data
Let A be the following 2x2 matrix: s 2s 0 t Find a subspace B of M2x2 where M2x2 = A (+) B 2. Relevant equations A ∩ B = {0} if u and v are in M2x2, then u + v is in M2x2 if u is in M2x2, then cu is in M2x2 3. The attempt at a solution Let B be the following 2x2 matrix: 0 0 r 0 Because they are both subspace, they intersect at the zero vector and thus the set {0}, the zero subspace, is a subspace of M2x2. We then have M2x2 = A (+) B: M2x2 = A + B /\ A ∩ B = {0} |
| Nov5-11, 07:17 PM | #2 |
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It also doesn't make sense to add a matrix - A - and a subspace - B. What is the exact wording of this problem? |
| Nov5-11, 07:20 PM | #3 |
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....
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| Nov5-11, 07:24 PM | #4 |
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Finding a subspace (possibly intersection of subspace?)This stuff, too. where {A|s,t in ℝ} ℂ M2x2(ℝ) s, t in what? |
| Nov5-11, 07:32 PM | #5 |
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This should make it easier haha
![]() In case the image isn't showing either, the symbol that isn't showing is the "R" for real numbers, so s,t in R and M(R) |
| Nov5-11, 07:38 PM | #6 |
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I take it then that you mean B is a subspace of the space of all two by two matrices with real entries. However, you do NOT mean that A is the "matrix" given. Rather, A is the subspace of all two by two matrices, with real entries, of the form
[tex]\begin{bmatrix}s & 2s \\ 0 & t\end{bmatrix}[/tex]. Saying that "[itex]A(+)B= M_{22}(R)[/itex]" means that for any numbers u, x, y, z, there exist numbers a, b, c, d such that [tex]\begin{bmatrix}s & 2s \\ 0 & t\end{bmatrix}+ \begin{bmatrix}a & b \\ c & d\end{bmatrix}= \begin{bmatrix}u & x \\ y & z\end{bmatrix}[/tex] Of course, then we must have [tex]\begin{bmatrix} a & b \\ c & d\end{bmatrix}= \begin{bmatrix}u- s & x- 2s \\ y & z- t\end{bmatrix}[/tex] Now, what relations must a, b, c, and d satisfy? |
| Nov5-11, 07:49 PM | #7 |
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Closure under addition and closure under multiplication?
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| Nov5-11, 08:00 PM | #8 |
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I barely see what it's asking...
Given A, I don't have a problem proving that A is a subspace of M22 -- just show there's closure under addition and multiplication. I can find a basis/span, etc. For this question, I'm somewhat lost. Since A + B = M22, then B = M22 - A, I'm assuming B has to follow the closure requirements, but is that it? It seems like I'm just missing something pretty big here... |
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