Potential and field at two electric plates

kirby2

fdsfds sdfs

Delphi51

Yes on both A and C. My explanation for A would be that work needs to be done to push a positive test charge from B to A against the force of the electric field. Your V=kq/r is obscure (unrelated to this question) because it is the absolute potential or work/charge for moving a charge from infinite distance into a position that is distance r away from charge q. It does tell you that the potential midway between the positive and negative plates is zero, though.

kirby2

and the other answers are wrong, correct?

Delphi51

Correct.