## Rotating Square Loop in Constant B-field

1. The problem statement, all variables and given/known data
 A square loop (length along one side = 20 cm) rotates in a constant magnetic field which has a magnitude of 2.0 T. At an instant when the angle between the field and the normal to the plane of the loop is equal to 20° and increasing at the rate of 10°/s, what is the magnitude of the induced emf in the loop? a. 13mV b. 0.27V c. 4.8mV d. 14mV e. 2.2mV
2. Relevant equations

$\epsilon$ = - $\frac{d\Phi}{dt}$

$\Phi$ = BAcos($\theta$) = BAcos($\omega$t)

$d\Phi$ = -BA$\omega$sin($\omega$t)

3. The attempt at a solution

I'm trying to study for an exam and I've got this practice question that I can answer but my answer never matches. I keep getting b as an answer and I'm not sure if it's right.

$\epsilon$ = BAcos($\omega$t) = (2T)(0.2m)2(10)sin(10t)

I use t = 2s since it asks for $\theta$ = 20° and I get

$\epsilon$ = (2T)(0.2m)2(10)sin(20) ≈ 0.27 V

Am I making a mistake or a wrong assumption anywhere or could it be the answer is incorrectly marked?

Thanks!
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 Using "10" might be fine inside the argument of the sine function, but if you're taking it outside when you take the derivative, you need to convert it to rad/s.
 Thanks, didn't think of that.

 Tags flux, magnetism