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3z-1+2√z=32This equation gets solved when we assume the z as |
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| May4-12, 10:14 AM | #1 |
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3z-1+2√z=32This equation gets solved when we assume the z as
3z-1+2√z=32
This equation gets solved when we assume the z as any variable's2 and turn that into a quadratic form. Is there any other way of solving this equation? |
| May4-12, 10:29 AM | #2 |
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Well, when we square stuff, which ammounts to basically the same thing: [itex]3z-33=-2\sqrt{z}\Longrightarrow 9z^2-198z+1089=4z\Longrightarrow 9z^2-202z+1089=0\Longrightarrow z_1=13.444\,,\,\,z_2=9[/itex] . As many times with these exercises, only the second number above is a solution to the original equation. DonAntonio |
| May4-12, 11:21 AM | #3 |
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But, the assumption thing looks simple enough. |
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