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Related rates differentiation problem |
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| Jul27-12, 11:32 PM | #18 |
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Related rates differentiation problem
35 * 4 = 140 for x, 25 * 4 = 100 for y; [itex]\frac{-2(150-140)*35+2*100*25}{\sqrt{(150-140)^{2}+ 100^{2}}}[/itex] = [itex]\frac{-2*10*35 + 5000}{\sqrt{10^{2} + 100^{2}}}[/itex] = [itex]\frac{-700 + 5000}{\sqrt{10100}}[/itex] = [itex]\frac{4300}{10\sqrt{101}}[/itex]
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| Jul27-12, 11:35 PM | #19 |
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Recognitions:
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[tex]\frac{-2(150-140) \cdot 35+2 \cdot 100 \cdot 25}{2\sqrt{(150-140)^{2}+ 100^{2}}}[/tex] (Also, don't use "*" for multiplication in LaTeX. Use "\cdot" instead.) |
| Jul27-12, 11:37 PM | #20 |
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I see, my mistake. I must have missed the 2 in the denominator.
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| Jul27-12, 11:39 PM | #21 |
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It would be about 21.39 km/hr
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| Jul27-12, 11:43 PM | #22 |
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Recognitions:
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That's what I got. You have to be careful with the algebra when solving Calculus problems. (Not easy -- I know.)
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