## Latent Heat (enthalpy) of Fusion changes with Pressure?

If the melting point depends on the pressure, does the latent heat of fusion also depend on the pressure? The equation relating the entropy of fusion to the enthalpy of fusion is given by:

$$\Delta H=T\Delta S$$

where T is, apparently, the temperature of melting. So, if the melting point increases with pressure, then as isentropic melting occurs the latent heat (enthalpy) of fusion decreases linearly?

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Recognitions:
 Quote by Hypatio If the melting point depends on the pressure, does the latent heat of fusion also depend on the pressure? The equation relating the entropy of fusion to the enthalpy of fusion is given by: $\Delta H=T\Delta S$ where T is, apparently, the temperature of melting. So, if the melting point increases with pressure, then as isentropic melting occurs the latent heat (enthalpy) of fusion decreases linearly?
$dH=C_p dT +(V-T \frac{\partial V}{\partial T}|_p}dp$
Just integrate along the phase boundary $T_\mathrm{melt}(p)$ for the two phases in equilibrium.