
#1
Nov1612, 04:27 PM

P: 35

1. The problem statement, all variables and given/known data
What happens to the frequency of oscillation if stiffness increases and why? 2. Relevant equations ? 3. The attempt at a solution Frequency increases but trying to figure out why. 



#2
Nov1612, 04:30 PM

P: 615

By stiffness I'm assuming you mean the spring constant, often known as k. It's found in Hooke's law F = kx where F is the force the spring is exerting and x is the distance from the equilibrium point.
Don't you have some equations relating the frequency of the oscillations of the springmass system and the spring constant of the spring? 



#3
Nov1612, 04:34 PM

P: 35





#4
Nov1612, 04:44 PM

P: 615

Stiffness in mass spring system
[itex]a = \left( 2 \pi f\right)^{2x}[/itex] ?
I don't recognize that equation >.> I'm very sorry do you recognize [itex]x \left( t \right) = Acos \left( \omega t  \phi \right)[/itex] where [itex]\omega = \sqrt{ \frac{k}{m}}[/itex] is the angular frequency of the oscillation, A is the amplitude and [itex]\phi[/itex] is the phase shift? 



#5
Nov1612, 04:53 PM

P: 35

I dint knew the 2nd equation but i get it now. stiffness is proportional to frequency according to that.but does the natural frequency of spring increases as well? 



#6
Nov1612, 05:03 PM

P: 615

angular frequency is just the natural frequency times 2π or [itex] \omega = 2 \pi f[/itex] 



#7
Nov1612, 05:04 PM

P: 35




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